3、LeetCode 题解 - Longest Substring Without Repeating Characters

2019-07-10

目录

翻译

给定一个字符串,找出其没有重复字符的最大子序列的长度。   例如,“abcabcbb”的无重复字符的最大子序列是“abc”,它的长度是 3。   “bbbbb”的最大子序列是“b”,它的长度是 1。

原文

Given a string, find the length of the longest substring without repeating characters.      For example, the longest substring without repeating letters for "abcabcbb" is "abc", which the length is 3.            For "bbbbb" the longest substring is "b", with the length of 1.    

Code 1(C++)

class Solution {
public:
    int lengthOfLongestSubstring(string s) {
        int len = s.Length;
        int head = 0, index = 0, maxLen = 0;
        bool[] exist = new bool[256];
        for (int i = 0; i < exist.Length; i++)  
            exist[i] = false;  
        while (index < len){
            if (exist[s[index]]){
                 maxLen = Math.Max(maxLen, index - head);
                 while (s[head] != s[index]){
                     exist[s[head]] = false;
                     head++;
                 }
                 head++; index++;
             }
             else{
                 exist[s[index]] = true;
                 index++;
             }
         }
         maxLen = Math.Max(maxLen, len - head);
         return maxLen; 
    }
};

Code 1 C

public class Solution
{
    public int LengthOfLongestSubstring(string s)
    {
        int len = s.Length;
        int head = 0, index = 0, maxLen = 0;
        bool[] exist = new bool[256];
        for (int i = 0; i < exist.Length; i++)
            exist[i] = false;
        while (index < len)
        {
            if (exist[s[index]])
            {
                maxLen = Math.Max(maxLen, index - head);
                while (s[head] != s[index])
                {
                    exist[s[head]] = false;
                    head++;
                }
                head++; index++;
            }
            else
            {
                exist[s[index]] = true;
                index++;
            }
        }
        maxLen = Math.Max(maxLen, len - head);
        return maxLen;
    }
}

Code 1 Java

public class Solution {
    public int lengthOfLongestSubstring(String s) {
        int len=s.length();
        int head=0,index=0,maxLen=0;
        boolean[] exist=new boolean[256];
        for(boolean e : exist)
            e=false;
        while(index<len){
            if(exist[s.charAt(index)]){
                maxLen=Math.max(maxLen, index-head);
                while(s.charAt(head)!=s.charAt(index)){
                    exist[s.charAt(head)]=false;
                    head++;
                }
                head++; index++;
            }
            else{
                exist[s.charAt(index)]=true;
                index++;
            }
        }
        return maxLen= Math.max(maxLen,len-head);
    }
}

Code 2 C++

static  int lengthOfLongestSubstring(string s)
{
    int ascii[256];
    for(int i=0; i<256; i++) ascii[i] = -1;
    int start = 0, ans = 0;
    int i;
    for(i=0; i<s.size(); i++){
       if( -1 != ascii[ s[i] ] ){
            if(ans < i-start) ans = i-start;
            for(int j=start; j<ascii[ s[i] ]; j++)
                 ascii[j] = -1;
            if(ascii[s[i]] + 1 > start )
                 start = ascii[s[i]] +1;
       }
       ascii[s[i]] = i;
    }
    if(ans < i-start) ans = i-start;
    return ans;
}
```